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In this blog, we are going to take a look at how to deploy a lambda code to AWS using Jenkins Free-Style Job based on the above flow diagram.
The following environment setup/pre-requisites required to achieve the above flow.
- Running Jenkins (Master/Slave) Machines
- SCM (Any – Bitbucket or GitHub) with your Source Code (In this example, I will show Java 8).
- AWS CLI must be installed where Jenkins is running either Master or Slave Machine.
- Identify/Create S3 Bucket Name
- Must-Have AWS Programmatic Access User which should be configured in AWS CLI with its Access Key and Secret Key
- Create a role which has Lambda Execution Access
- Must be Known about what is Lambda Function Name and Handler Name.
- Install Lambda Plugin in Jenkins
Deploy Lambda Code in Jenkins:
- Create a FreeStyle Job in Jenkins
- Configure where your source code is running in Jenkins
- In Build Environment (Execute Shell)
- Supply Gradle or Maven Clean build which will generate Jar as zip file under distribution
- write a simple Linux command to traverse to the location
- Use AWS CLI command to copy your zipe file from local to S3 location, for eg.,
- aws s3 cp test-lambda.zip s3://test-lambda-operation/test-lambda.zip
- In Post Build Action -> Select “AWS Lambda Deployment” plugin and Fill the appropriate information like below examples
- Lambda Plugin also has capability to update Environment Variable and Subnet and Security Details (In case your lambda needs to run under VPC)
- Click on the Save button.
- That’s it, Now Build Jenkins Job
This will kick start the job by copying zip file in local to S3 Object and code/configuration will get updated on AWS. The appropriate configuration and environment details will be updated in AWS Lambda Function.
Note: The above example is one way of deploying Lambda Function to AWS, there are other examples like Terraform, AWS Cloud formation template, Core AWS CLI commands etc., using Jenkins.
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